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Unlock Your Perfect Minecraft World: Discover the Ultimate Seed Map Viewer! - Carbonext

📅 February 27, 2026 👤 scraface

Feb 27, 2026

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Total number of 1×1 grid positions: \( 4 \times 3 = 12 \).
Number of ways to choose 3 distinct positions: \( \binom{12}{3} = \fra...
Now, favorable outcomes: all 3 positions in different rows.
There are 4 rows, choose 3 distinct rows: \( \binom{4}{3} = 4 \).
Each chosen row has 3 columns, so for each row, pick 1 position: \( 3...
But this counts selections per row order — since we are selecting unor...
So, number of favorable selections:
\binom{4}{3} \times 3^3 = 4 \times 27 = 108
Thus, probability:
P = \frac{108}{220} = \frac{27}{55}

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