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For the walkway with radius \(5r\): - Carbonext

📅 February 27, 2026 👤 scraface

Feb 27, 2026

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rac{b}{a} = -rac{-4}{1} = 4
Since \( x = \sqrt{v} \), each positive root \( x_i \) corresponds to...
But wait: the sum of the roots in \( x \) is 4, but the sum of the roo...
\sum x_i^2 = \left( \sum x_i
ight)^2 - 2\sum_{i<j} x_i x_j
From the cubic \( x^3 - 4x^2 + 5x - 6 = 0 \), the symmetric sums are:
\( \sum x_i = 4 \)
\( \sum_{i<j} x_i x_j = 5 \)
\sum x_i^2 = 4^2 - 2 \cdot 5 = 16 - 10 = 6
Since each \( v_i = x_i^2 \), the sum of the roots \( v_i \) is:

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