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Home » Dividing both sides by \(\sqrt3\), we get: - Carbonext

Dividing both sides by \(\sqrt3\), we get: - Carbonext

📅 February 27, 2026 👤 scraface

Feb 27, 2026

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ho$:
ho^2 = 4
ho\sin\phi
Recall in spherical coordinates:
ho^2 = x^2 + y^2 + z^2, \quad
ho\sin\phi = \sqrt{x^2 + y^2}
x^2 + y^2 + z^2 = 4\sqrt{x^2 + y^2}
Let $r = \sqrt{x^2 + y^2}$. Then:
r^2 + z^2 = 4r \Rightarrow r^2 - 4r + z^2 = 0 \Rightarrow (r - 2)^2 +...
This is a sphere of radius 2 centered at $(2, 0, 0)$ in cylindrical co...

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