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Home » But without r, cannot compute unless baseline is zero-sided. - Carbonext

But without r, cannot compute unless baseline is zero-sided. - Carbonext

📅 February 26, 2026 👤 scraface

Feb 26, 2026

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📌 \text{مجموع الأطوال} = 3.2 + 7.8 = 11.0 \text{ بوصة}

📌 \text{متوسط الطول} = \frac{11.0}{2} = 5.5 \text{ بوصة}

📌 متوسط طول القطعتين من الخيط هو \boxed{5.5} بوصة.

📌 السؤال: لدى جاري 3 جالونات من الخل واستخدم 7/4 جالونات في الطهي. ما هو الكسر من جالون الخل المتبقي لدى جاري؟

📌 \text{الخل المتبقي} = 3 - \frac{7}{4}

📌 أولاً، نحول 3 إلى كسر بمقام 4:

📌 \frac{12}{4} - \frac{7}{4} = \frac{12 - 7}{4} = \frac{5}{4}

📌 لدى جاري \boxed{\frac{5}{4}} جالونًا من الخل المتبقي.

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u = rac{3 \pm \sqrt{9 - 4}}{2} = rac{3 \pm \sqrt{5}}{2}.
So \( u = rac{3 + \sqrt{5}}{2} \) or \( u = rac{3 - \sqrt{5}}{2} \).
Now recall \( u = rac{x+y}{x-y} \). Let \( r = rac{x}{y} \), assumin...
e 0\). Then:
rac{x+y}{x-y} = rac{r+1}{r-1}.
Set this equal to each value of \(u\):
Case 1:** \( rac{r+1}{r-1} = rac{3 + \sqrt{5}}{2} \)
2(r+1) = (3 + \sqrt{5})(r - 1)
2r + 2 = (3 + \sqrt{5})r - (3 + \sqrt{5})
2r + 2 = (3 + \sqrt{5})r - 3 - \sqrt{5}

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