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Area of the square not covered by the circle: - Carbonext

📅 February 27, 2026 👤 scraface

Feb 27, 2026

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Let \( v = \sqrt{u} \), so \( u = v^2 \). Substitute:
v^2 \cdot v - 5v^2 + 6v = 0 \quad \Rightarrow \quad v^3 - 5v^2 + 6v =...
v(v^2 - 5v + 6) = 0.
Factor quadratic:
v(v - 2)(v - 3) = 0.
So, \( v = 0, 2, 3 \). Since \( u = v^2 \), the corresponding roots ar...
All roots are non-negative, so valid.
Sum of roots: \( 0 + 4 + 9 = 13 \).
Define \( M(u) = u - \frac{u^4}{4} \) for all real \( u \). If \( n \)...
We compute recursively:

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